Sin4x Integration
dx&line2=%5Cmathrm%7BSolution:%5C:%7D%5Cfrac%7B1%7D%7B4%7D%5Ccos(4x)%2BC "Sin4x Integration")
![d.∫0π ∣∣ sin4x∣∣ dx=2∫0π/2 sin4xdx Using walli's formula, 2[4⋅23⋅1 ]2π =8..](https://classroom-images.cdn.askfilo.com/classroom/1680011276449_gpfgigja_536492.jpg "Sin4x Integration")
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