Path Connected
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![general topology - How to use a continuous function on $[0,1]$ to prove ...](https://i.sstatic.net/IijXW.png)






![G is path-connected: We can connect any two patterns [X] and [Y ] by ...](https://www.researchgate.net/profile/Vu-Dinh/publication/280104797/figure/fig3/AS:667109860311043@1536062793130/G-is-path-connected-We-can-connect-any-two-patterns-X-and-Y-by-adding-a-new-root-r_Q640.jpg)



















